Horse Racing

Given a horse race with 5 gates and no stopwatch find the 1st-3rd place winners of a pool of 25 horses  assuming that each horse will race consistently.  How many and what races must be run in order to determine the winners ?

SOLUTION:

This question is an interesting one. Let’s start by asking ourselves, what are our limitations? Well, we don’t have a stopwatch so we can’t time the horses. That means that we can’t compare the race times of each horse – otherwise we could simply have 5 races of 5 horse each and pick out the 3 fastest times to get the 3 fastest horses. Remember that we can only race 5 horses in each race otherwise we could just have one race with 25 horses, pick the 3 fastest, and we would be done!!!.

We are going to use matrix approach to visualize this problem.First divide 25 horses into 5 groups to get a 5×5 matrixby putting each horse randomly into a 5×5 matrix.where each row represent a race and each column represent the rank in the corresponding race.

1)First  5 races will give the winner of each race and the order(rank) in which they should appear in the matrix.Now we will get the matrix where each row represent a race and each column represent the rank in the corresponding race e.g.  horse X2.3 got the third rank in the second race.Note that the 10 horses X?.4-X?.5 were eliminated in the first five 5 races by virtue that they cannot place 1st-3rd.

X1.1 X1.2 X1.3 X1.4 X1.5
X2.1 X2.2 X2.3 X2.4 X2.5
X3.1 X3.2 X3.3 X3.4 X3.5
X4.1 X4.2 X4.3 X4.4 X4.5
X5.1 X5.2 X5.3 X5.4 X5.5

2)A winner of 6th race of  the individual winners ( X?.1 i.e. first column) of the first 5 races will give the clear 1st place winner(Suppose here X1.1) and suppose if  the 2nd and 3rd winner of this race is X2.1 and X3.1 then the remainder of the last two rows can be eliminated along with the horses labeled X3.3, X3.2, X2.3 as they will not be able to place 2nd or 3rd either.

X1.1 X1.2 X1.3 X1.4 X1.5
X2.1 X2.2 X2.3 X2.4 X2.5
X3.1 X3.2 X3.3 X3.4 X3.5
X4.1 X4.2 X4.3 X4.4 X4.5
X5.1 X5.2 X5.3 X5.4 X5.5

3) The 7th and last race will be between non-eliminated horses labeled as  X1.2, X1.3, X2.1, X2.2, X3.1 which will give  2nd and 3rd place winner.

So a total of 7 races of 5 horses each is required to find the 1st-3rd place winners…Was it tough!!! 😉

If that was not enough for you ……

If you want to determine a fourth place winner, then you need at most only one more race.

  • If  X1.2 wins and X1.3 and X3.1 share 4th or 5th places in the last race, then  X1.2,  X2.1 and X2.2 take 2nd, 3rd and 4th places respectively overall without another race.
  • If in the last race, X1.2 and X1.3 take 4th or 5th places respectively and X3.3 takes 2nd then X1.4, X2.2 and X3.2 must race to determine the 4th place overall.
  • Otherwise, the final races 3rd place winner must face off against the neighbor to the final races 2nd place winner for 4th place overall

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